Question

3x+10 =0 has how many solution

Answer 1

$Given \: linear \: equation \: in \: one$ $variable \: x \: is : \red{ 3x + 10 = 0 }$

$\therefore \green {It \: has \: only \:one \: solution.}$

Explanation :

$Given \: equation \: 3x + 10 = 0$

/* Subtract bothsides by 10, we get */

$\implies 3x + 10 - 10 = -10$

$\implies 3x = -10$

/* Dividing both sides by 3 , we get */

$\implies \frac{3x}{3} = \frac{-10}{3}$

$\implies x = \frac{-10}{3}$

Therefore.,

$\green { \frac{-10}{3} \: is \:the \: only \: one \: solution}$

$\green {\:of \: given \: equation . }$

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Answer 2

x = -10/3 .

Solution :-

=> 3x + 10 = 0

=> 3x = -10

=> x = -10/3

.°. -10/3 is the only one solution of given equation .

Verification :-

=> 3x + 10 = 0

=> 3 × -10/3 + 10 = 0

=> -10 + 10 = 0

=> 0 = 0

Hence verified!!