3x-10 degrees and 2x+15 degrees are complementary find them
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Here is your answer mate ..
1) 3x - 10 + 2x + 15 = 90
5x - 10 + 15 = 90
5x + 5 = 90
5x = 90 - 5
5x = 85
x = 85/ 5
x = 17
Now substitute x in the given angles
3(17) - 10 = 41
2(17) + 15 =49
so the angles are 41° and 49°
3)5x + 14 + x + 46 = 180
6x + 60 = 180
6x = 180 - 60
6x = 120
x = 20
Now substitute x in the given angles
5(20)+14=114
20+46 = 66
so the angles are 114° and 66° .
hope it helps u
please mark my answer as a brainliest.....
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