(3x^2+1/x)(3x^2-1/x)
Answers
Answered by
2
Answer:
9x^4-1/(x^2)
Step-by-step explanation:
it is 8n the form of
(a+b)(a-b)=(a^2-b^2)
(3x^2+1/x)(3x^2-1/x)=((3x^2)^2-(1/x)^2)
=9x^4-1/(x^2)
Answered by
3
Answer:
(3x^2+1/x)(3x^2-1/x)
this is in the form of (a+b)(a-b)
so , (a+b)(a-b)= a^2 -b^2
given that ,
a = 3x^2 , b = 1/x.....
=> (3x^2)^2 - (1/x)^2
=>(9x^4) - (1/x^2)
hope it helpss
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