Math, asked by vinaychauhan54, 11 months ago

(3x^2+1/x)(3x^2-1/x)​

Answers

Answered by sriammanstore
2

Answer:

9x^4-1/(x^2)

Step-by-step explanation:

it is 8n the form of

(a+b)(a-b)=(a^2-b^2)

(3x^2+1/x)(3x^2-1/x)=((3x^2)^2-(1/x)^2)

=9x^4-1/(x^2)

Answered by cuteangel12
3

Answer:

(3x^2+1/x)(3x^2-1/x)

this is in the form of (a+b)(a-b)

so , (a+b)(a-b)= a^2 -b^2

given that ,

a = 3x^2 , b = 1/x.....

=> (3x^2)^2 - (1/x)^2

=>(9x^4) - (1/x^2)

hope it helpss

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