(3x^2-10x-8),(9x^2-4)
allysia:
what I have to do ?
Simplification?
Or factorization?
It's better to do both :)
Answers
Answered by
3
(3x^2-10x-8)
3x^2 -6x -4x-8
3x (x -2) -4(x-2)
(x-2)(3x-4)
x-2 =0
x = 2
3x-4 =0
3x=4
x= 3/4
(9x^2-4)
Use the identity a^2 -b^2
(3x)^2 -(2)^2
(3x+2)(3x-2)
3x+2 =0
3x =-2
x= -2/3
3x -2 =0
3x =2
x=2/3
3x^2 -6x -4x-8
3x (x -2) -4(x-2)
(x-2)(3x-4)
x-2 =0
x = 2
3x-4 =0
3x=4
x= 3/4
(9x^2-4)
Use the identity a^2 -b^2
(3x)^2 -(2)^2
(3x+2)(3x-2)
3x+2 =0
3x =-2
x= -2/3
3x -2 =0
3x =2
x=2/3
Similar questions