Question

3x^2+13x+k=0 (using x=4)​

Answer 1

HEYA MATE !

x=4

3×(4)²+13×4+k=0

3×16+13×4+k=0

48+52+k=0

100+k=0

k=(-100)

hope it helps

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Answer 2

$3(x) {}^{2} + 4x + k = 0 \\ \\ 3(16) + 13(16) + k = 0 \\ \\ 48 + 208 + k = 0 \\ \\ k = - 256$

may it's helpful to you