Question

3x^2+13x+k=0 (using x=4)​

Answer 1

hey dear!

3x16+52+k=0

48+52+k=0

k= -100

thanks!!

Answer 2

3x^2 + 13x + k =0

Given x=4

by putting it, we get =>

3×16 + 13×4 + k = 0

48 + 52 + k = 0

100 + k = 0

k = -100 Ans.

$nazmin \: akter$

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