Question

3x^2+14x+8 solve by splitting middle term method.​

Answer 1

Answer:

3x^2+14x+8=0

3x^2+12x+2x+8=0

3x(x+4) +2(x+4) =0

(3x+2) (x+4) =0

x=-2/3, -4

Answer 2

Answer:

$3x^{2} +14x+8$

$3x^{2} +12x+2x+8$

$3x(x+4)+2(x+4)$

$(3x+2)(x+4)$