Question

3x^2-17x+24 by quadratic formula

Answer 1

Step-by-step explanation:

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Answer 2

Given :

• 3x² - 17x + 24

To Find :

• Zeroes of the given polynomial by quadratic formula

Solution :

Quadratic formula :

➨ x = - b ± √ ( b² - 4ac ) / 2a

Here

• a = 3
• b = -17
• c = 24

➨ x = [ - ( - 17 ) ± √ ( (-17 )² - 4 * 3 * 24 ) ] / 2 * 3

➨ x = [ 17 ± √ ( 289 - 288 ) ] / 6

➨ x = [ 17 ± √ 1 ] / 6

➨ x = [ 17 ± 1 ] / 6

Case 1 :-

➨ x = [ 17 + 1 ] / 6

➨ x = 18 / 6

➨ x = 3

Case 2 :-

➨ x = [ 17 - 1 ] / 6

➨ x = 16 / 6

➨ x = 8 / 3

Zeroes of the polynomial are -8/3 and 3