Question

3x^2+19x+30 factorise by splitting the !iddle term​

Answer 1

Answer:

Factor

19

out

3x²+19(x)+30

Rewrite 19 as 9 plus 10

3x²+(9+10)x+30

Apply the distributive property.

3x²+9x+10x+30

Factor out the greatest common factor from each group

Group the first two terms and the last two terms.

(3x²+9x)+10x+30

Factor out the greatest common factor (GCF) from each group.

3x(x+3)+10(x+3)

Factor the polynomial by factoring out the greatest common factor,

x+3.(x+3)(3x+10)

Step-by-step explanation:

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Answer 2

Answer:

$= 3 {x}^{2} + 19x + 30 \\ = 3 {x}^{2} + 10x + 9x + 30 \\ = x (3x + 10) \: 3(3x + 10) \\ = (x + 3)(3x + 10) \\ \\ x = - 3 \: \: x = - \frac{10}{3}$

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