Question

√3x^2 -2√2x-2√3=0 find the root of the quadratic equation by factorisation .

Answer 1

Answer:

i hope you are satisfied with my solution

Answer 2

$\sqrt{3x {}^{2} } - 2 \sqrt{2} x - 2 \sqrt{3 } = 0 \\ \sqrt{3x {}^{2} } - 3 \sqrt{2} x - + \sqrt{2} x - 2 \sqrt{3} \\ \sqrt{3} x ( {x} - \sqrt{6} ) + \sqrt{2} (x - \sqrt{6} ) \\ ( \sqrt{3} x + \sqrt{2} )( \sqrt{x} - \sqrt{6} ) \\ x = \binom{ - \sqrt{2} }{ \sqrt{3} } x = \sqrt{6}$

hope it helpss.........................