Question

√3x^2 -2√2x-2√3=0 solve by quadratic formula​

Answer 1

Answer:

I am not fake but I am broken

Answer 2

Answer:

roots are 3√2/√3 and -√2/√3

Step-by-step explanation:

by using quadratic formula,

-b±√b²-4ac

2a

-(-2√2)±√(-2√2)²-4(√3)(-2√3)

2√3

2√2±√8+24

2√3

2√2±√32

2√3

2√2±4√2

2√3

√2±2√2

√3

first root is,

√2+2√2

√3

3√2

√3

√3×√3×√2

√3

√3×√2

√6

second root is,

√2-2√2

√3

-√2

√3

Thank me later if this helps u :)