Question

√3x^2-2√3x-2√3=0 find the roots of quadratic equation​

Answer 1

Answer:

$\alpha + \beta = \frac{ - ( - 2 \sqrt{3)} }{ \sqrt{3} } \\ = 2 \\ \alpha \beta = \frac{ - 2 \sqrt{3} }{ \sqrt{3 } } \\ = - 2$