Question

3x^2-2√6 + 2 ≈ 0 ( solve the following quardratic equation by factorisation)

Answer 1

3x²-2√6x+2=0
3x²-(√6+√6)x+2=0
3x²-√6x-√6x+2=0
√3*√3x²-√2*√3x-√2*√3x+√2*√2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3

Answer 2

HELLO DEAR,

3X² - 2√6X + 2 = 0

=> 3X² - √6X - √6X + 2 =0

=> √3x(√3x -√2) - √2( √3x - √2)

=> (√3x -√2)(√3x-√2) = 0

=> x = -√2/√3

AND

X = -√2/√3

I HOPE ITS HELP YOU DEAR,
THANKS