Question

3x ^ 2 + 2(x + 2) - 3x * (2x + 1)​

Answer 1

Answer:

Given :-

➪ 3x² + 2(x + 2) - 3x(2x + 1)

Solution :-

➪ 3x² + 2(x + 2) - 3x(2x + 1) = 0

➭ 3x² + 2x + 4 - 6x² - 3x = 0

➭ 3x² - 6x² + 2x - 3x + 4 = 0

➭ - 3x² - x + 4 = 0

➭ - (3x² + x - 4) = 0

➭ 3x² + x - 4 = 0

➭ 3x² + (4 - 3)x - 4 = 0

➭ 3x² + 4x - 3x - 4 = 0

➭ x(3x + 4) - 1(3x + 4) = 0

➭ (3x + 4) (x - 1) = 0

➭ (3x + 4) = 0

➭ 3x + 4 = 0

➭ 3x = - 4

➭ x = - 4/3

Either,

➭ (x - 1) = 0

➭ x - 1 = 0

➭ x = 1

∴ The value of x is - 4/3, 1