3x^2-25x+28=0 by quadratic formula
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Answer:
Step-by-step explanation
3x²-25x+28
A=3
B= -25
C=28
Quadratic formula -
[-b±√(b²-4ac)]/2a
-(-25)±√[(-25)²-4×3×28]/ 2×3
25±√[625-336] / 6
(25±289)/6
The two roots are
-44 and 314/6
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