Question

3x^2-2root6x+2=0 find the roots of the equation by appling the quadratic formula..​

Answer 1

Step-by-step explanation:

Given that 3x^2-2√6x+2=0

3x^2-√6x-√6x+2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2) (√3x-√2) =0

x=√2/3,√2/3

Answer 2

Answer:

$x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{2 \sqrt{6 } \frac{ + }{} \sqrt{ {( - 2\sqrt{6} )}^{2} + 4 \times 3 \times 2 } }{ {2 \times 3} } \\ x = \frac{2 \sqrt{6} \frac{ + }{} \sqrt{24 + 24} }{6} \\ x = \frac{2 \sqrt{6 } \frac{ + }{} \sqrt{48} }{6} \\ x = \frac{2 \sqrt{6} \frac{ + }{} 4\sqrt{3} }{6} = \frac{2 \sqrt{3}( \sqrt{2 } \frac{ + }{}2) }{6} \\ x = \frac{ \sqrt{2} \frac{ + }{} 2 }{ \sqrt{3} } \\ therefore \\ x = \sqrt{ \frac{2}{3} } \: \: or - \frac{2}{ \sqrt{3} }$