Question

√3x^2 +√2x-2√3=0 determine the nature of roots for each of the quadratic equation​

Answer 1

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Answer 2

The given quadratic equation​ have two distinct real root.

Step-by-step explanation:

The given quadratic equation is

$\sqrt{3}x^2+\sqrt{2}x-2\sqrt{3}=0$

A quadratic equation is $ax^2+bx+c=0$.

If $b^2-4ac<0$, then the equation have two complex roots.

If $b^2-4ac=0$, then the equation have equal real roots.

If $b^2-4ac>0$, then the equation have two distinct real roots.

In the given equation,

$a=\sqrt{3},b=\sqrt{2},c=-2\sqrt{3}$

$b^2-4ac=(\sqrt{2})^2-4(\sqrt{3})(-2\sqrt{3})=2+24=26$

Since $b^2-4ac>0$, therefore, the given quadratic equation​ have two distinct real root.

#Learn more

Determine the nature of the roots of the equation.

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