Question

√3x^2+√2x-2√3=0
Find nature of root

Answer 1

Answer:

a=√3, b=√2, c=-2√3

D=b²-4ac

D=(√2)²-4(-2√3)(√3)

D=2+8(3)

D=2+24

D=26

D>0, so the roots are real and distinct.