√3x
²– 2x – √3 = 0, by factorization method find the roots
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√3x²-2x-√3=0
√3x²-3x+1x-√3=0
√3x(x-√3)+1(x-√3)=0
(√3x+1)(x-√3)=0
√3x+1=0 x-√3=0
√3x= -1 x=√3
x= -1/√3
Therefore the roots are -1/3 and √3
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