Question

√3x^2-√2x-3√3=0
Please solve and send solution​

Answer 1

Solution:

√3x² - √2x - 3√3 = 0

Here , given equation is a quadratic equation

Finding the value of x using quadratic formula

x = - b ± √b² - 4ac/2a

Where,

• b : coefficient of x = -√2
• a : coefficient of x² = √3
• c : constant term = -3√3

→ x = - (-√2 )± √(-√2)² - 4(√3)(-3√3)/2(√3)

→ x = √2 ± √2 + 36/2√3

→ x = √2 ± √38/2√3

Taking common & substituting 2 = √2 × √2

→ x = √2 [ 1 ± √19 ]/( √2 ) ( √2 ) ( √3 )

→ x = [ 1 ± √19 ]/√2 ( √3 )

→ x = 1 + √19/√6 or 1 - √19/√6

Hence , x = 1 + √19/√6 or 1 - √19/√6

Answer 2

Given :  √3x² - √2x - 3√3 = 0

To Find :

Solution:

ax² + bx + c = 0

roots =  (-b ± √(b² - 4ac) )/2a

 √3x² - √2x - 3√3 = 0

a = √3

b = - √2

c = -3√3

=>  x = (- (- √2) ± √( (√2)² - 4√3 (-3√3) )/2√3

=>   x =   (√2  ±√38) )/2√3

=>  x =   (√2  ± √38 )/2√3

=>  x = √2  (1  ± √19 )/2√3

=>  x =   (1  ± √19 )/√2√3

=>  x =   (1  ± √19 )/√6

x =   (1  ± √19 )/√6

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