Question

(3x+2)/(2x-3)=-3/2 find value of x

Answer 1

$\large\sf\red{\underline{\underline{Question:}}}$

• $\dfrac{3x+2}{2x-3}=-\dfrac{3}{2}$ Find the value of x.

$\large\sf\red{\underline{\underline{Solution:}}}$

$\longmapsto\dfrac{3x+2}{2x-3}=-\dfrac{3}{2}$

• Cross -Multiplying:

$\dashrightarrow\sf 2(3x-2)=-3(2x-3)$

$\dashrightarrow\sf 6x-4=-6x+9$

•Adding 6x on both sides :

$\dashrightarrow \sf 6x + \green{6x} -4= \cancel{-6x}+ \cancel{\green{6x}} + 9$

$\dashrightarrow\sf 12x-4=9$

•Adding 4 on both sides :

$\dashrightarrow\sf 12x\cancel{-4}+\cancel{\green{4}} =9 +\green{4}$

$\dashrightarrow\sf 12x=13$

• Dividing both sides by 12:

$\dashrightarrow\sf\dfrac{12x}{\green{12}}=\dfrac{13}{\green{12}}$

$\dashrightarrow\sf x =\dfrac{13}{12}$

Therefore,

• Value of x is 13/12.