Question

(3x+2) ÷ (2x-3) =8
Please find answer

Answer 1

Answer:

How to solve your question

Your question is

(

3

+

2

)

(

2

−

3

)

=

8

\frac{(3x+2)}{(2x-3)}=8

(2x−3)(3x+2)=8

Solve

1

Multiply all terms by the same value to eliminate fraction denominators

3

+

2

2

−

3

=

8

\frac{3x+2}{2x-3}=8

2x−33x+2=8

(

2

−

3

)

(

3

+

2

2

−

3

)

=

(

2

−

3

)

⋅

8

(2x-3)(\frac{3x+2}{2x-3})=(2x-3) \cdot 8

(2x−3)(2x−33x+2)=(2x−3)⋅8

2

Cancel multiplied terms that are in the denominator

3

Re-order terms so that constants are on the left

4

Distribute

5

Subtract

2

2

2

from both sides of the equation

6

Simplify

7

Subtract

1

6

16x

16x

from both sides of the equation

8

Simplify

9

Divide both sides of the equation by the same term

10

Simplify

Hope it helps you!