Question

3x^2-2x-40/3x+10
$3{x}^{2} - 2x - 40 \div 3x + 10$
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Answer 1

Answer:

3x^2-2x-40/3x+10 = x-4

Step-by-step explanation:

Answer 2

Answer:

$3 {x}^{2} - 2x - 40. \div 3x + 10. \\ = > (3x + 10)(x) = > 3 {x}^{2} + 10x. \\ = > 3 {x}^{2} - 2x - 40 - 3 {x}^{2} - 10x. \\ - 12x - 40. \\ (3x + 10.)( - 4) \\ = > - 12x - 40 + 12x + 40. \\ = > 0. \: \\ so \: the \: remainder \: is \: 0. \\ and \: quotient \: is \: x - 4. \\ hopes \: its \: help \: u \: \\ mark \: it \: a s \: a \: brainlist \: answer. \:$