Question

3x^2-2x-8=0 solve the using factorisation​

Answer 1

Step-by-step explanation:

$3x {}^{2} - 2x - 8 = 0 \\ 3x {}^{2} - (6 - 4)x - 8 = 0 \\ 3x {}^{2} - 6x + 4x - 8 = 0 \\ 3x(x - 2) + 4(x - 2) = 0 \\ (x - 2)(3x + 4) = 0 \\ \\ (x - 2) = 0 \\ x = 2 \\ \\ 3x + \\ \\ \\ 3x + 4 = 0 \\ 3x = - 4 \\ x = \frac{ - 4}{3}$