Question

∫(3x−2)2x2−x​+1dx. ∫(3x−2)
2x
2
−x
​
+1dx​

Answer 1

Solution

I=∫(3x+2)

2x

2

−x+1

dx

for such questions write linear term as the first derivative of quadrant term.

i.e., 3x−2=A(

dx

d

(2x

2

−x+1))+B

3x−2=A[4x−1]+B

3x−2=4Ax+B−A

4A=