Math, asked by wanderersoul, 1 month ago

3x^2-35x+32 factorise​

Answers

Answered by prathamchoudhary969
2

Answer:

(x-1) (3x-32)

Step-by-step explanation:

given that ; 3x²-35x+32

:- 3x² -32x-3x+32

:- x(3x-32) -1(3x-32)

:- (x-1) (3x-32)

if we find the value of find we can get

x=1, x=32/2

thank you

Answered by rahul7288
1

Answer:

here is your answer

Step-by-step explanation:

Step by Step Solution

STEP1:Equation at the end of step 1

(3x2 - 35x) + 32

STEP2:Trying to factor by splitting the middle term

 2.1     Factoring  3x2-35x+32 

The first term is,  3x2  its coefficient is  3 .

The middle term is,  -35x  its coefficient is  -35 .

The last term, "the constant", is  +32 

Step-1 : Multiply the coefficient of the first term by the constant   3 • 32 = 96 

Step-2 : Find two factors of  96  whose sum equals the coefficient of the middle term, which is   -35 .

     -96   +   -1   =   -97     -48   +   -2   =   -50     -32   +   -3   =   -35   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -32  and  -3 

                     3x2 - 32x - 3x - 32

Step-4 : Add up the first 2 terms, pulling out like factors :

                    x • (3x-32)

              Add up the last 2 terms, pulling out common factors :

                     1 • (3x-32)

Step-5 : Add up the four terms of step 4 :

                    (x-1)  •  (3x-32)

             Which is the desired factorization

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