|3x-2|+|3x-4|+|3x6|>=12
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Answer:
1) |x|=x, x> 0
3x-2+3x-4+3x6>=12
6x-6+18>=12
6x+12>=12
6x>=0
x>=0
2)|x|=-x,x<0
-(3x-2)-(3x-4)+3×6>=12
-6x+6+18>=12
-6x+24>=12
-6x>=-12
x<=2
Taking intersection of both 1) and 2)
x belong to (-infinity,0] U [0,2]
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