Math, asked by greenflame8622, 1 year ago

|3x-2|+|3x-4|+|3x6|>=12

Answers

Answered by ak10063

1

Answer:

1) |x|=x, x> 0

3x-2+3x-4+3x6>=12

6x-6+18>=12

6x+12>=12

6x>=0

x>=0

2)|x|=-x,x<0

-(3x-2)-(3x-4)+3×6>=12

-6x+6+18>=12

-6x+24>=12

-6x>=-12

x<=2

Taking intersection of both 1) and 2)

x belong to (-infinity,0] U [0,2]

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