3x^2-4root 3x +4=0
find the nature of roots of the following quadratic equation if the real root exist find them
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Answer:
32 and 32
Step-by-step explanation:
3x2−43x+4=0
a=3,b=−43,c=4
Discriminant D=b2−4ac
=(−43)2−4(3)(4)=48−48=0
⇒D=0
⇒ Two roots are equal.
The roots are
=2a−b±D=2×343±0=32,32
Hence, the roots are 32and32
Hope it helps you
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