Question

3x^2-4root3x+4 real root exist find them​

Answer 1

Hello Friend...

Solution:-

given that

3x² - 4√3 X + 4 = 0

Using Formula:-

$x = \frac{ - b ± \sqrt{ {b}^{2} \: - 4ac } }{2a}$

Here,

a = 3 , b = -4√3 and C = 4

Now,

$x \: = \frac{ - ( - 4 \sqrt{3} ) \:± \: \sqrt{ {(-4 \sqrt{3}) }^{2} - 4 \times 3 \times 4} }{2 \times 3}$

$x = \frac{4 \sqrt{3} \: ± \: \sqrt{48 \: - 48} }{6}$

$x = \frac{4 \sqrt{3} }{6}$

$x = \frac{2 \sqrt{3} }{3} \: \: answer$

Hope it helps... :-)