Question

3X-2/4x-3=6x+1/8x-3.find the value of x ​

Answer 1

Answer:

If the equation given is:

$\frac{3x -2}{4x -3} = \frac{6x + 1}{8x - 3}$

then x = $\frac{9}{11}$

If the equation given is:

$3x$ $- \frac{2}{4x}$ $- 3$ = $6x$ $+ \frac{1}{8x}$ $- 3$

then x = $\sqrt{\frac{-5}{24} }$

Step-by-step explanation:

If the equation given is:

$\frac{3x -2}{4x -3} = \frac{6x + 1}{8x - 3}$

=> 24$x^{2}$ - 25x + 6 = 24$x^{2}$ - 14x - 3

=> -11x = -9

∴ x = $\frac{9}{11}$

If the equation given is:

$3x$ $- \frac{2}{4x}$ $- 3$ = $6x$ $+ \frac{1}{8x}$ $- 3$

=> $-3x$ $= \frac{1}{8x} + \frac{2}{4x}$ $= \frac{5}{8x}$

∴ $x^{2} = - \frac{5}{24}$

∴ x = $\sqrt{\frac{-5}{24} }$