Question

√3x^2-4x+34 + √3x^2-4x-11 =9

Answer 1

Answer:

No real solutions

Step-by-step explanation:

Given in the question an expression

√3x²- 4x + 34 + √3x² - 4x - 11 = 9

Let's solve your equation step-by-step.

Step 1

3.464102x² − 8x +23 = 9

Step 2

Subtract 9 from both sides.

3.464102x²  −8x +23 − 9 = 9 − 9

3.464102x² −8x + 14 = 0

Step 3

Use quadratic formula

with

a=3.4641016151377544

b=-8

c=14

x =-b±√b²-4ac / 2a

x = 8±√64-4(3.46)(14) / 2(3.36)

x = 8±√64-4(3.46)(14) / 2(3.36)

x = 8±√-129.76 / 2(3.36)

Answer 2

Answer:

Step-by-step explanation:

Take 3x^2 = y

:- √y+34 - √y-11=5

squaring both sides

y+34 + y-11 - 2√y+34-y+11 = 25

2y +25 -25 = 2√y+34-y+11

2y=2√y+34+y-11

Squaring both sides

4y^2=4(45)

4y^2=2y-25

4y^2-2y+25=0

u will get the values of y

put √3x^2+4 instead of y and solve.