Question

(3x^2-4x+6x^3-5) + (8x^3-4x^2+5x+5)

Answer 1

Answer:

$x(14x^{2}-x+1)$

Explanation:

$(3x^{2}-4x+6x^{3}-5)+(8x^{3}-4x^{2}+5x+5)$

=$3x^{2}-4x+6x^{3}-5+8x^{3}-4x^{2}+5x+5$  [Open the Brackets]

=$6x^{3}+8x^{3}+3x^{2}-4x^{2}-4x+5x$    [Arrange them into group according to like terms]  

=$14x^{3}-x^{2}+x$  

=$x(14x^{2}-x+1)$

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