Math, asked by khandelwalkanak14, 3 months ago

3x-2/5x-1=3x+1/5x+2
help me​

Answers

Answered by dishanthooda76
0

Answer:

x=-5

Step-by-step explanation:

Multiply the numbers

3

1

2

5

1

=

3

+

1

5

+

2

3x{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{2}{5}}}x-1=3x+\frac{1}{5} \cdot x+2

3x−1⋅52​x−1=3x+51​⋅x+2

3

2

5

1

=

3

+

1

5

+

2

3x{\color{#c92786}{-\frac{2}{5}}}x-1=3x+\frac{1}{5} \cdot x+2

3x−52​x−1=3x+51​⋅x+2

2

Combine multiplied terms into a single fraction

3

2

5

1

=

3

+

1

5

+

2

3x-\frac{2}{5}x-1=3x+\frac{1}{5} \cdot x+2

3x−52​x−1=3x+51​⋅x+2

3

+

2

5

1

=

3

+

1

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{1}{5} \cdot x+2

3x+5−2x​−1=3x+51​⋅x+2

3

Combine multiplied terms into a single fraction

again

3

+

2

5

1

=

3

+

1

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{1}{5}x+2

3x+5−2x​−1=3x+51​x+2

3

+

2

5

1

=

3

+

1

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{1x}{5}+2

3x+5−2x​−1=3x+51x​+2

4

Multiply by 1

3

+

2

5

1

=

3

+

1

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{1x}{5}+2

3x+5−2x​−1=3x+51x​+2

3

+

2

5

1

=

3

+

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{x}{5}+2

3x+5−2x​−1=3x+5x​+2

5

Add  

1

1

1

to both sides of the equation

3

+

2

5

1

=

3

+

5

+

2

3x+\frac{-2x}{5}-1=3x+\frac{x}{5}+2

3x+5−2x​−1=3x+5x​+2

3

+

2

5

1

+

1

=

3

+

5

+

2

+

1

3x+\frac{-2x}{5}-1+{\color{#c92786}{1}}=3x+\frac{x}{5}+2+{\color{#c92786}{1}}

3x+5−2x​−1+1=3x+5x​+2+1

6

Simplify

Add the numbers

Add the numbers

again

3

+

2

5

=

3

+

5

+

3

3x+\frac{-2x}{5}=3x+\frac{x}{5}+3

3x+5−2x​=3x+5x​+3

7

Subtract  

3

3x

3x

from both sides of the equation

3

+

2

5

=

3

+

5

+

3

3x+\frac{-2x}{5}=3x+\frac{x}{5}+3

3x+5−2x​=3x+5x​+3

3

+

2

5

3

=

3

+

5

+

3

3

3x+\frac{-2x}{5}{\color{#c92786}{-3x}}=3x+\frac{x}{5}+3{\color{#c92786}{-3x}}

3x+5−2x​−3x=3x+5x​+3−3x

8

Simplify

Combine like terms

Combine like terms

again

2

5

=

5

+

3

\frac{-2x}{5}=\frac{x}{5}+3

5−2x​=5x​+3

9

Multiply all terms by the same value to eliminate fraction denominators

2

5

=

5

+

3

\frac{-2x}{5}=\frac{x}{5}+3

5−2x​=5x​+3

5

2

5

=

5

(

5

+

3

)

5 \cdot \frac{-2x}{5}=5(\frac{x}{5}+3)

5⋅5−2x​=5(5x​+3)

10

Simplify

Cancel multiplied terms that are in the denominator

Distribute

Cancel multiplied terms that are in the denominator

2

=

+

1

5

-2x=x+15

−2x=x+15

11

Subtract  

x

x

from both sides of the equation

2

=

+

1

5

-2x=x+15

−2x=x+15

2

=

+

1

5

-2x{\color{#c92786}{-x}}=x+15{\color{#c92786}{-x}}

−2x−x=x+15−x

12

Simplify

Combine like terms

Combine like terms

again

3

=

1

5

-3x=15

−3x=15

13

Divide both sides of the equation by the same term

3

=

1

5

-3x=15

−3x=15

3

3

=

1

5

3

\frac{-3x}{{\color{#c92786}{-3}}}=\frac{15}{{\color{#c92786}{-3}}}

−3−3x​=−315​

14

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

5

x=-5

x=−5

dsfsef

Answered by pshreyansh461
1

Answer:

(3x-2)(5x+2)=(3x+1)(5x-1)

15x2+6x-10x-4=15x2-3x+5x-1

-4x-4=2x-1

-4x-2x=-1+4

-6x=3

x=3/-6

x=-1/2

hope u understan

thanx

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