3x^2-5x+2=0 by nature root method
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Step-by-step explanation:
If D is equal to 0, then we get two roots which are equal and same. If D is less than 0, then we get roots which are imaginary or unreal. Since D is greater than 0 in this case, we get two real and distinct roots. Hence solved !!
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3x²-5x+2=0
compare equation with ax²+bx+c=0
a=3,b=-5,c=2
b²-4ac=(-5)²-4×3×2
=25-24
=1
b²-4ac<0
therefore the roots of quadratic equation is real and unequal.
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