Question

(3x^2+5x-7)(x-1)-(x^2-2x+3)(x+4)​

Answer 1

Step-by-step explanation:

$(3 {x}^{2} + 5x - 7)(x - 1) - ( {x}^{2} - 2x + 3)(x + 4) \\ (3 {x}^{3} - 3 {x}^{2} + 5 {x}^{2} - 5x - 7x + 7) - ( {x}^{3} + 4 {x}^{2} - 2 {x}^{2} - 8x + 3x + 12) \\ (3 {x}^{3} + 2 {x}^{2} - 12x + 7) - ( {x}^{3} + 2 {x}^{2} + 5x + 12) \\ 3 {x}^{3} + 2 {x}^{2} - 12x + 7 - {x}^{3} - 2 {x}^{2} - 5x - 12 \\ 2 {x}^{3} - 17x - 5$