3x/2-5y/3=-2;x/3+y/2=13/6 in substitution method
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Answer:
The value of x is 2 and y is 3.
Step-by-step explanation:
……………………..(1)
……………………….(2)
Consider equation
By taking LCM for the denominator 2 and 3 we get the LCM as 6
9x – 10y = -12 ……………………….. (3)
Consider equation 2
By taking LCM for the denominator 3 and 2 we get the LCM as 6
2x + 3y = 13 …………………………(4)
By solving equation (3) and (4) we get
2x = 13-3y
x=13-3y/2 …………………………(5)
Put the value of x in eqn 3 we get
9[13-3y/2] – 10y =-12
117-27y-20y = -24 [By taking LCM and solving it]
117-47y=-24
-47y=-24-117
-47y=-141
Y=-141/-47
Y=3
Now put the value of y =3 in (5)
x=13-3(3)/2
x=13-9/2
x=4/2
x=2
Therefore we have x=2 and y=3
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