3x\2 - 5y/3 = -2 , x/3 + y/2 = 13/6 solve the elimination, cross multiple or graphical method 3 method Slovenia question
Answers
From equation 1 :
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Answer:
3x−35y=−2multiplyingtheeqnby66(23x−35y=−2)218x−330y=−129x−10y=−12...(1)
\begin{lgathered}\frac{x}{3} + \frac{y}{2} = \frac{13}{6} \\ \\ \bf multiplying \: the \: {eq}^{n} \: by \: 6 \\ \\ 6( \frac{x}{3} + \frac{y}{2} = \frac{13}{6} ) \\ \\ \frac{6x}{3} + \frac{6y}{2} = 13 \\ \\ 2x + 3y = 13 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ...(2)\end{lgathered}3x+2y=613multiplyingtheeqnby66(3x+2y=613)36x+26y=132x+3y=13...(2)
From equation 1 :
\begin{lgathered}9x = - 12 + 10y \\ \\ \bf x = \frac{ - 12 + 10y}{9}\end{lgathered}9x=−12+10yx=9−12+10y
\begin{lgathered}2( \frac{ - 12 + 10y}{9} ) + 3y = 13 \\ \\ \frac{ - 24 + 20y}{9} + 3y = 13 \\ \\ \frac{ - 24 + 20y + 27y}{9} = 13 \\ \\ - 24 + 47y = 13 \times 9 \\ \\ - 24 + 47y = 117 \\ \\ 47y = 117 + 24 \\ \\ y = \frac{141}{47} \\ \\ \bf y = 3\end{lgathered}2(9−12+10y)+3y=139−24+20y+3y=139−24+20y+27y=13−24+47y=13×9−24+47y=11747y=117+24y=47141y=3
\begin{lgathered}2x + 3(3) = 13 \\ \\ x + 9 = 13 \\ \\ x = 13 - 9 \\ \\ \bf x = 4\end{lgathered}2x+3(3)=13x+9=13x=13−9x=4