Question

3x^2+60xy-288y^2
pls help me​

Answer 1

Answer:

x^2+20xy-96y^2

Step-by-step explanation:

3)x^2+20xy-96y^2

Answer 2

Given:

We have given an equation which is  $3x^2+60xy-288y^2$.

To Find:

We have to simplify the equation?

Step-by-step explanation:

• We have given an quadratic equation which is written below

        $3x^2+60xy-288y^2$

• First of all we take 3 common from the whole equation we get the

        $3(x^2+20xy-96y^2)$

• For solving the above equation we wil make the factors of equation for whcih we will write the middle term is in addition form form of two factors of 96

• Factors of 96 are 2,2,2,2,2,3
• Now we can see 24 aqnd 4 are factor of 96 also 24-4=20

        $3(x^2+24xy-4xy-96y^2)$

• Now take the numer common from the first two terms and also from last two terms

       $3(x(x+24y)-4y(x+24y))$

• Now we take the elements common from both the term we get

         $3(x+24y)(x-4y)$

Hence , the factos are 3(x+24y)(x-4y).