Math, asked by anusobikvta, 8 months ago

3x^2-6x +1 =0
Solve using completing the square method

Answers

Answered by biligiri
0

Answer:

3x² - 6x + 1 = 0

x² - 6x/3 + 1/3 = 0

=> x² - 2x = -1/3

=> x² - 2x + (1)² = -1/3 + (1)²

=> (x - 1)² = 2/3

=> x - 1 = ±√(2/3)

=> x = 1 + √(2/3) and x = 1 -√(2/3)

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