3x^2-6x +1 =0
Solve using completing the square method
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Answer:
3x² - 6x + 1 = 0
x² - 6x/3 + 1/3 = 0
=> x² - 2x = -1/3
=> x² - 2x + (1)² = -1/3 + (1)²
=> (x - 1)² = 2/3
=> x - 1 = ±√(2/3)
=> x = 1 + √(2/3) and x = 1 -√(2/3)
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