3x^2+6x-160 please reply asap
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Answer:
(3x2 + 6x) - 160 = 0
Factoring 3x2+6x-160 => 3x2 + 6x - 160 = 0
Find the Vertex of y = 3x2+6x-160
Root plot for : y = 3x2+6x-160
Axis of Symmetry (dashed) {x}={-1.00}
Vertex at {x,y} = {-1.00,-163.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-8.37, 0.00}
Root 2 at {x,y} = { 6.37, 0.00}
Solving 3x2+6x-160 = 0 by Completing The Square.
x2+2x-(160/3) = 0
x2 + 2x - (160/3) = 0
has two solutions:
x = -1 + √ 163/3
or
x = -1 - √ 163/3
Solving 3x2+6x-160 = 0 by the Quadratic Formula.
answer : x =(-6-√1956)/6=-1-1/3√ 489 = -8.371
x =(-6+√1956)/6=-1+1/3√ 489 = 6.371
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