Math, asked by roulettegupta, 10 months ago

3x^2+6x-160 please reply asap

Answers

Answered by sashragavi
0

Answer:

(3x2 +  6x) -  160  = 0

 Factoring  3x2+6x-160 =>    3x2 + 6x - 160  = 0

Find the Vertex of   y = 3x2+6x-160

Root plot for :  y = 3x2+6x-160

Axis of Symmetry (dashed)  {x}={-1.00}  

Vertex at  {x,y} = {-1.00,-163.00}  

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-8.37, 0.00}  

Root 2 at  {x,y} = { 6.37, 0.00}

Solving   3x2+6x-160 = 0 by Completing The Square.

x2+2x-(160/3) = 0

x2 + 2x - (160/3) = 0

  has two solutions:

 x = -1 + √ 163/3

  or

 x = -1 - √ 163/3

Solving    3x2+6x-160 = 0 by the Quadratic Formula.

answer :  x =(-6-√1956)/6=-1-1/3√ 489 = -8.371

x =(-6+√1956)/6=-1+1/3√ 489 = 6.371

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