Question

3x^2-6x+2=0 . solve it by using completing square method​

Answer 1

Answer:

x = (√5/3 - 1) , -(√5/3) - 1

Step-by-step explanation:

Step 1 : Make the cofficient of x ² = 1. So, divide the whole term separately by 3.

3x²/3 - 6x/3 + ⅔= 0

x² - 2x + ⅔ = 0

Step 2 : Move the constant term to the right side.

x²-2x = ⅔

Step 3: Add the square of half of cofficient of x on both the sides.

{ Cofficient of x is 2 and half is 1 }p

x²-2x + (1)² = ⅔ + (1)²

By 2nd identify a²-2ab+b² = (a- b)²

(x-1)² = ⅔ + 1

LCM = 3

(x + 1)² = (2+3)/3

(x+1)² = 5/3

x + 1 = (√5/3)

x + 1 = ± √5/3

When x is positive

So, x = +(√5/3) - 1

When x is negative:-

x = -(√5/3) -1

So, x = +(√5/3) - 1 and

x = -(√5/3)-1

Answer 2

Answer:

3x^2-6x+2=0 . solve it by using completing square method

Step-by-step explanation:

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