Math, asked by sneha38770, 11 months ago

3x^ -2√6x +2 =0

3x ^{2}  -  \sqrt{6} x -  \sqrt{6} x   + 2

Answers

Answered by Siddharta7
2

3x^2 - 2√6 +2=0

3x^2 - √6 - √6 +2=0

3x^2 - √(2×3) - √(2×3) + 2=0

3x^2 - (√2)(√3) - (√2)(√3) + 2=0

√3 (√3 -√2 ) -√2 (√3 - √2 )=0

(√3 - √2) (√3 - √2)=0

Hence x =√(2/3) & x =√(2/3) are roots of the equation

Answered by faizan1733
0

Answer:

I dont no about this type of questions.S, sorry bro i cant help you

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