Question

3x^2 + 7x + p = 0. ( x = - 2)
x^2 + k( 4x +k-1) + p= 0 ( roots are equal)

Answer 1

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Here,

x = – 2 is the root of the equation

3x^2 + 7x + p = 0

⇒ 3(– 2)2 + 7(– 2) + p = 0

⇒ p = 2

Root of the equation

x^2 + 4kx + k^2 – k + 2 = 0  are equal.

⇒ b^2 – 4ac = 0

⇒ 16k^2 – 4(k^2 – k + 2) = 0

⇒ 3k^2 + k – 2 = 0

⇒ (3k – 2)(k + 1) = 0

⇒ k =  2  ÷ 3  , − 1

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