(3x^2+9x+6)-(8x^2+3x-10)+(2x+4)(3x-7)
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Answer:
(3x²+9x+6)-(8x²+3x-10)+(2x+4)(3x-7)
=3x²+9x+6-8x²-3x+10+6x²-14x+12x-28
=x²+4x-12
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