Question

(3x-2)* and (x+48)* find the value of x​

Answer 1

Step-by-step explanation:

x^3-x^2=48 (has either 1 or 3 real solutions, because it is a polynomial with the highest power being odd)

x^2*(x-1)=16*3

x^2*(x-1)=4*4*3

x^2*(x-1)=4^2*(4-1)

x1=4 is a solution

Now do polynomial division

(x^3-x^2–48):(x-4)=x^2+3x+12

Apply the quadratic formula

x=-3+-sqrt(3^2-4*1*12)

x=-3+-sqrt(-39)=-3+-sqrt(39)*i

Therefore the solutions are:

x1=4

x2=-3/2+i*sqrt(39)/2

x3=-3/2-i*sqrt(39)/2

Answer 2

Step-by-step explanation:

(3x-2) (x+48)

4x -144x +2x +96

4x -2x = 144+96

2x= 240

x= 120

I hope it's help you

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