3x^2+kx+81=0 find the value of k in quadratic equation
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the question u asked is hard to find because u`ve got 2 unknown variables wich are k and x so i guess i have to tell that inorder to find k we have to know the value of x.
sorry that i couldn`t help u
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Answer:
Let, X = 2
P(x)= 3x^2 +kx +81 =0
P(2)= 3(2)^2 +k(2) +81 =0
P(2)= 3(4) +k(2) = -81
P(2)= k(2) = - 81 - 12
P(2)= k = - 91/2
So, k = - 45.5
Hope it helps u
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