Question

3x+2 root 5 x-5=0 find roots of the quadratic equation by factorisation​

Answer 1

Answer:

Plz check the ques once again!!

3x²+2√5x-5=0

3x²+(3√5-1√5)x-5=0

3x²+3√5x-√5x-5=0

3x(x+√5)-√5(x+√5) =0

(x+√5)(3x-√5)=0

So X = -√5 or √5/3

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Answer 2

$\huge\sf{ \underline{ \underline{Question}}}$

$\sf{Find\:roots\:of\: quadratic\: equation}$

$\huge\sf{ \underline{ \underline{Answer}}}$

$\sf{-\sqrt{5} \:, \: \dfrac{\sqrt{5}}{3}}$

$\huge\sf{ \underline{ \underline{Solution}}}$

$\sf{3\ x^{2}+2\sqrt{5}x-5\:=\:0}$

$\sf{3\ x^{2}+3\sqrt{5}x-\sqrt{5}x-5\:=\:0}$

$\sf{3x(x+\sqrt{5})-\sqrt{5}(x+\sqrt{5})\:=\:0}$

$\sf{(x+\sqrt{5})(3x-\sqrt{5})\:=\:0}$

$\sf{x\:=\:-\sqrt{5} \:, \: \dfrac{\sqrt{5}}{3}}$