3x+2(x+2)=20-(2x-5)
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- 3x + 2 (x +2) = 20 - (2x -5)
- 3x(x + 2) + 2(x + 2) = 20 - 2x + 5
- 3x² + 6x + 2x + 4 = 25 - 2x
- 3x² + 6x + 2x + 2x = 25 - 4
- 3x² + 10x = 21
- 3x² + 10x - 21 = 0
Answered by
1
Answer:
3x + 2 (x +2) = 20 - (2x -5)
3x(x + 2) + 2(x + 2) = 20 - 2x + 5
3x² + 6x + 2x + 4 = 25 - 2x
3x² + 6x + 2x + 2x = 25 - 4
3x² + 10x = 21
3x² + 10x - 21 = 0
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