3x+2 (x+2)=20-(2x-5) how to solve this equation
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Answered by
19
3x+2x+4=20-2x+5
5x+4=25-2x
5x+2x=25-4
7x=21
x=21/7
x=3
5x+4=25-2x
5x+2x=25-4
7x=21
x=21/7
x=3
viru5:
plz solve it in lhs and rga
rhs
this is in that method only
pls mark me as brainliest
This the way this question is to be solved viru5
Answered by
2
The answer comes out to be 3. X=3. Multiply the 2 on the left hand side , then you will get 3x + 2x +4 = 20-2x+5. by rearrangement we can obtain the value of x to be 3
ok. Then you have to do the method given below
I don't understand
3X +2(X) +2(2) = 20- 2X - (-5X)
3X +2X +4 = 20- 2X +5X
5X +4 = 20 -2X +5
It's not 5X on the rhs, but it is 5
5X + 2X = 20 + 5 - 4
7X = 25 - 4
7X = 21
X = 21/7 = 3
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