3x+2÷x-3-1/3=2x+3÷x-3-1/2
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SOLUTION:-
3x+ 2/x - 2x-3/x = -3-1/2+3+1/3
= x+ 2/x -3/x = (-3+2)/6
= (x^2 +2-3)/2 = -1/6
= x^2-1= -1/3
= x^2 = -1/3+1
= x^2 = (-1+3)/3
x =![\sqrt[]{ \frac{2}{3} }](https://tex.z-dn.net/?f=+%5Csqrt%5B%5D%7B+%5Cfrac%7B2%7D%7B3%7D+%7D+ "\sqrt[]{ \frac{2}{3} }")
3x+ 2/x - 2x-3/x = -3-1/2+3+1/3
= x+ 2/x -3/x = (-3+2)/6
= (x^2 +2-3)/2 = -1/6
= x^2-1= -1/3
= x^2 = -1/3+1
= x^2 = (-1+3)/3
x =
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